Talk:Hidden Power (move)/Calculation

Standards

Isn't there normally something on the discussion page that tells what about the article needs doing? Iliekmudkips 21:17, 29 September 2007 (UTC)

Manual of style. Needs cleaning up, it's essentially a giant wall of text. TTEchidna 00:27, 30 September 2007 (UTC)

I'm working on a new version of this article, located here, with "/IV" and "/Type" subpages. A I am not english-native speaker, I would appreciate somebody's help, especially with math terms.Piotr mil 02:27, 22 June 2008 (UTC)

Why not just make these pages in the main namespace? Or even better, work on them in some kind of sandbox, and then put them in the main namespace? --Martonimos_{((Argh|Blargh))} 02:30, 22 June 2008 (UTC)

I just want to prepare them, as I'm not sure how should they look. I was trying to make a sandbox, but it was considered as spamming and making "useless Myspace junk", so I moved here to work. Piotr mil 04:01, 22 June 2008 (UTC)

I understand that. But when preparing them, there's no need to save the changes to the site, especially if they're not ready yet. Try copying the code to wordpad. When you want to see how it looks, copy it all, go to the sandbox, paste it in over whatever's there already, and preview it. There's no need to save.

Like I said, I appreciate what you're doing, so I'm sorry I'm coming off as such a hard-ass here. I just want to prevent you from spamming the recent changes with a lot of edits to the same page. --Martonimos_{((Argh|Blargh))} 05:32, 22 June 2008 (UTC)

That's ok. I hope you appreciate the article. Piotr mil 16:33, 27 June 2008 (UTC)

Maths

Can't the calculations and explanations for the Hidden Power formula be easier? I'm not good at maths, and I don't think many people here are Math professors.FireHazard 02:24, 24 August 2008 (UTC)

No, that equation is simplified as far as it could possibly go. ^Moldy_Orange 02:25, 24 August 2008 (UTC)

Its actually quite simpleGood Day;DCM

Math professors??? Multiplying, adding and dividing is a basic knowledge. You don;t need to have four brains or be able to bend spoons to understand it. I know, however, that this might be a little bit confusing when you look at this for the first time, but - again - try to do some math excercises, and you will understand it. Pokémon games are based on math (shinyness, game data structures, IVs, EVs, etc.) like everything else. And - yes - I simplified this article to the maximum. The previous one was quite messy. Piotr mil 12:11, 13 September 2008 (UTC)

I added a few links to Wikipedia math articles to make the article a little bit easier to understand. Hopefully I won't be punished for too many wp: likns :D Piotr mil 12:23, 13 September 2008 (UTC)

GEN II

How Did It Work In Generation Two? TorchicBlaziken ^{(talk•edits)} 12:47, 21 December 2008 (UTC)

I'm pretty sure it worked the same way it's listed here now.--jw 13:08, 14 February 2009 (UTC)

Is there any particular reason why it wouldnt have worked the same way in Gen II, TorchicBlaziken? --sHoggard - rookie Pokéwiz 21:21, 9 August 2010 (UTC)

Bits?

I feel like there should be an illustration of the reasons behind this seemingly complex calculation involving remainders, that reason being the binary representation of the IVs. I was thinking something along the lines of this (using the pikachu's stats in the example)

Relative bit weights
MSB	DisableAbility	IsEgg	Sp. Def	Sp. Atk	Speed	Defense	Attack	HP	LSB
	0	0	11111	11110	11111	11111	11111	11110

111111 = 63

101110 = 46

--Null Set 02:42, 11 November 2009 (UTC)

The way I sure the games do it, is for the type, each variable equals the last bit in its IV and, for the Power, each Variable equals the second to last bit. I just put it a section below this one. It is concerned with the possible outcomes of Hidden Power but it makes mention to what you're getting at.The Professor 20:31, 25 June 2010 (UTC)

Possible HP Combos

The Section about the number of possible Hidden Power combinations is not entirely correct. The section says that since there are 32 possible values for each IV, the number of possible combinations is 32^6. If you get down to purely what the outcome is, then there are only 4^6 combinations. If you graph the outcomes for for the possible numbers this is what you get.

	0	1	2	3	4	5	6	7	8	9	10
Type	0	1	0	1	0	1	0	1	0	1	0
Power	0	0	1	1	0	0	1	1	0	0	1

There are four possible out comes for each IV Value; 00, 01, 10 and, 11. For any one who doesn't know binary these values equal the numbers 0, 1, 2 and, 3. Basically, you take the binary version of the IV and look at the last two bits to get the the outcome. This means that even though each IV is a number 0-31, the outcome boils down to a number 0-3. So there are 4 significant values for each IV, and there are 6 IV's so there are 4^6 (2^12) combinations for Hidden Power. That comes out to be 4096 possible outcomes. Far less than this article's stated 32^6(1073741824) outcomes. For any one who is confused about all of this I can explain it in further detail. Tell me watcha think! The Professor 20:21, 25 June 2010 (UTC)

Uhmm.... I'm not sure, if you have read the article correctly. I wrote the bit about 32^6 and wrote it's far too big... and then I wrote about 4^6....So.... I really don't get, what's your point, you have just copied the article here -__- Piotr mil 12:05, 20 July 2010 (UTC)

Really, divided out of 15?

It seems kind of stupid that the game developers would do such an uneven job of distributing Hidden Power. Simply dividing it by 4 gives a perfectly uniform distribution. Are you sure that the way it is now is correct? Ztobor 03:42, 23 July 2010 (UTC)